
definition - What is Convolution? - Mathematics Stack Exchange
Sep 6, 2015 · The definition of convolution is known as the integral of the product of two functions
Meaning of convolution? - Mathematics Stack Exchange
I am currently learning about the concept of convolution between two functions in my university course. The course notes are vague about what convolution is, so I was wondering if anyone could giv...
What is convolution, how does it relate to inner product?
Oct 25, 2022 · My final question is: what is the intuition behind convolution? what is its relation with the inner product? I would appreciate it if you include the examples I gave above and correct me if I am …
What is the convolution of a function - Mathematics Stack Exchange
Sep 12, 2024 · What is the convolution of a function f f with a delta function δ δ? Ask Question Asked 11 years, 2 months ago Modified 1 year, 4 months ago
Can someone intuitively explain what the convolution integral is?
I'm having a hard time understanding how the convolution integral works (for Laplace transforms of two functions multiplied together) and was hoping someone could clear the topic up or link to sour...
Definition of Convolution - Mathematics Stack Exchange
Aug 2, 2023 · This expression differs from the common definition of convolution. I'm having trouble understanding why we utilize the conventional definition of convolution in cases like these.
Definition of convolution? - Mathematics Stack Exchange
A shift-invariant linear operator T T is completely determined by its impulse response T(δ) = f T (δ) = f (where δ δ is the Dirac delta function). You can show that for any function g g, T(g) = f ∗ g T (g) = f ∗ …
Convolution: Laplace vs Fourier - Mathematics Stack Exchange
Are there real world examples when it is better to use laplace instead of fourier to compute a convolution? And vice versa. Fourier can use negative numbers (as in 'integrates from minus infinity to
real analysis - On the closedness of $L^2$ under convolution ...
Since the Fourier Transform of the product of two functions is the same as the convolution of their Fourier Transforms, and the Fourier Transform is an isometry on L2 L 2, all we need find is an L2 L 2 …
Proving commutativity of convolution $(f \\ast g)(x) = (g \\ast f)(x)$
Here is something I've sometimes wondered about. If f g f, g are both nonnegative proving commutativity of convolution can be done without a tedious change of variable. Indeed, let X X be a random …