Isai E. asked • 03/26/15 A wooden cylinder of height 8 cm and radius 3 cm is cut in two along a vertical axis of symmetry.

May 12, 2020 · With a vertical axis of symmetry, we have the equation of the parabola as. y = a(x-h) 2 + k. where (h,k) is the vertex. The vertex is given as (0,0), so h = 0 and k = 0. Therefore, …

Katie R. asked • 08/06/20 Find an equation for the conic section with the given properties. The parabola that passes through the point (8, −2), with vertex V(4, −1) and vertical axis of symmetry

The vertex form of a parabola with a vertical axis of symmetry is y = a(x-h) 2 + k where (h,k) is the location of the vertex and a is a constant, We know (h, k) = (0, 2) so the equation becomes:

Fujushi S. asked • 09/28/21 Find the standard equation of the parabola which satisfies the given conditions: vertex (-5, -7), vertical axis of symmetry, through the point P(7, 11)

May 20, 2014 · The standard form of a parabola with a vertical axis of symmetry [like my example] is (y-k) 2 =4p(x-h), where p is the directed distance between the vertex and focus (and also …

Clara D. asked • 12/03/20 The parabola that passes through the point (8, −2), with vertex V(2, −1) and vertical axis of symmetry

Apr 5, 2013 · where the value of 'a' determines whether the parabola opens upwards of downwards (i.e., the parabola opens upwards if a>0 and opens downwards if a<0) and the …

Sep 4, 2020 · x has the quadratic term since the line of symmetry is vertical. y-k=-a(x-h)^2 with (h,k)=(-4,3) and (x,y) = (0,-1) plug in the values and solve for a-1-3 = -a(0+4)-4 = -4a. a=1. y-3 …

Apr 10, 2014 · I had to find the coordinates of the vertex and the equation of the axis of symmetry for the parabola given the by the equation h(x)=-1/2x to the 2nd power +4x-8 and the answer I …