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  1. arrays - php implode with quotes - Stack Overflow

    31 No, the way that you're doing it is just fine. implode() only takes 1-2 parameters (if you just supply an array, it joins the pieces by an empty string).

  2. How to implode array with key and value without foreach in PHP

    Jul 11, 2012 · Using explode to get an array from any string is always OK, because array is an always in standard structure. But about array to string, is there any reason to use predefined string in codes? …

  3. PHP, add a newline with implode - Stack Overflow

    If you wrap your implode in the the <pre> tags, you can see it is working properly. Additionally, your arguments are backwards on your implode function, according to current documentation.

  4. Easiest way to implode () a two-dimensional array? [duplicate]

    6 If one simply wants to implode a single array "column" as in this case, then the simplest thing to do is:

  5. php - Build a dynamic INSERT query from the keys and values of an ...

    Apr 8, 2025 · Also, implode() doesn't care about the keys in the array, so array_values() is needless. This unexplained snippet is not protected against strings which contain one of the characters used as …

  6. What is the difference between implode () & join ()

    So although explode and implode are unarguably way more dramatic-sounding, I would vote for join as a more universal way to express the concatenation of every value of an array into a string.

  7. Implode an array with ", " and add "and " before the last item

    This array holds a list of items, and I want to turn it into a string, but I don't know how to make the last item have a &amp;/and before it instead of a comma. 1 =&gt; coke 2=&gt; sprite 3=&gt; f...

  8. Implode an array with JavaScript? - Stack Overflow

    Nov 10, 2010 · 0 array.join was not recognizing ";" how a separator, but replacing it with comma. Using jQuery, you can use $.each to implode an array (Note that output_saved_json is the array and tmp is …

  9. Error: implode(): Argument #1 ($pieces) must be of type array

    Sep 9, 2023 · Closed last year. Error: implode (): Argument #1 ($pieces) must be of type array, string given Here is my code and have been receiving same errors. What can I do?

  10. How to implode a vector of strings into a string (the elegant way)

    I needed the actual string representation after the implode, so I used imploded.str() to get a std::string. Also, for those who don't want the delimiter as the last part of the string, use the pop_back() method …